14x^2+37-42=(7x-6)

Solution for 14x^2+37-42=(7x-6) equation:

14x^2+37-42=(7x-6)

We move all terms to the left:

14x^2+37-42-((7x-6))=0

We add all the numbers together, and all the variables

14x^2-((7x-6))-5=0


We calculate terms in parentheses: -((7x-6)), so:

(7x-6)

We get rid of parentheses

7x-6

Back to the equation:

-(7x-6)


We get rid of parentheses

14x^2-7x+6-5=0

We add all the numbers together, and all the variables

14x^2-7x+1=0

a = 14; b = -7; c = +1;
Δ = b2-4ac
Δ = -72-4·14·1
Δ = -7
Delta is less than zero, so there is no solution for the equation